0

Guest

Courses New

The parabolas y2=$ax and x2=4by intersect orthogonally at point P(x1,y1) where x1,y1=0 is not possible then (A)b=a2 (B)b3=a2 (C)b=a3 (D)None of these.

The parabolas y2=$ax and x2=4by intersect orthogonally at point P(x1,y1) where x1,y1=0 is not possible then
(A)b=a2
(B)b3=a2
(C)b=a3
(D)None of these.

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
148 Points
14 years ago

Dear Jayati

y2=4ax

x2=4by

 

if these curve intersec orthogonally ,then tangent at heir point of intersection will also intersect orthogonall

 slope of tangent at y2=4ax  is  m1 = 2a/y1 

 sinece y1=0 so tangent is y axis

 

slope of tangent at x2=4by  is  m2 = x1/2b 

 sinece x1=0 so tangent is x axis

so these two tangent is perpendicular

 so these curve always intersect for all value of a,b

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very

quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

Other Related Questions on Differential Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More