Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        The parabolas y2=\$ax and x2=4by intersect orthogonally at point P(x1,y1) where x1,y1=0 is not possible then
(A)b=a2
(B)b3=a2
(C)b=a3
(D)None of these.```
7 years ago

147 Points
```										Dear Jayati
y2=4ax
x2=4by

if these curve intersec orthogonally ,then tangent at heir point of intersection will also intersect orthogonall
slope of tangent at y2=4ax  is  m1 = 2a/y1
sinece y1=0 so tangent is y axis

slope  of tangent at x2=4by  is   m2 = x1/2b
sinece x1=0 so  tangent is x axis
so these two tangent is perpendicular
so these curve always intersect for all value of a,b
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details