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akash kashyp Grade: Upto college level
`        |x^2+4x+3|+2x+5=0 solve`
7 years ago

147 Points
```										Dear akash
|x^2+4x+3|+2x+5=0
|x^2+4x+3| =-(2x+5)
so for solution exists
2x+5 ≤0
x≤-2.5
now check for x^2+4x+3≤0
(x+3)(x+1)≤0
-3 ≤ x≤-1
case 1      x≤-3
x^2+4x+3 =-(2x+5)
or x^2+6x+8| =0
x=-4 and -2
-2 is not a solution
case 2    -3 <x≤-2.5

-(x^2+4x+3) =-(2x+5)

x^2+2x-2 =0
x= -1 ±√3
so x= -1 -√3  is accepted solution

so final solution is x =-4 and -1-√3
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.
```
7 years ago
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