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akash kashyp Grade: Upto college level
        

|x^2+4x+3|+2x+5=0 solve

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear akash


|x^2+4x+3|+2x+5=0


|x^2+4x+3| =-(2x+5)


so for solution exists 


 2x+5 ≤0


x≤-2.5


now check for x^2+4x+3≤0


                   (x+3)(x+1)≤0


                       -3 ≤ x≤-1


 case 1      x≤-3


x^2+4x+3 =-(2x+5)


or x^2+6x+8| =0


   x=-4 and -2   


 -2 is not a solution


case 2    -3 <x≤-2.5



-(x^2+4x+3) =-(2x+5)



 


 


 



 x^2+2x-2 =0


 x= -1 ±√3


  so x= -1 -√3  is accepted solution


 


so final solution is x =-4 and -1-√3


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Badiuddin

7 years ago
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