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Jithu A Prasad Grade: 12
        

∫1⁄1+x2+y2dx

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Jithu


I = ∫1⁄(1+x2+y2)  dx


I = ∫1⁄√(1+y2)2+x2)  dx 


 


   = 1/ √(1+y2)   tan -1 { x/√(1+y2)}  +  C


 


here y is taken as constant because nothing is given about y


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7 years ago
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