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        limit x tends to zero  f(x) + log(1- 1/e^f(x) - log(f(x)) =0
find f(0)
7 years ago

bharat bajaj
IIT Delhi
123 Points
										$\lim_{x\rightarrow 0}f(x) + log( 1 - \frac{1}{e^{f(x)}} - log f(x) = 0$$f(0) + log( 1 - \frac{1}{e^{f(0)}} - log f(0) = 0$$-f(0) = log( 1 - \frac{1}{e^{f(0)}} - log f(0)$$Say f(0) = t$$e^{-t} = 1 - \frac{1}{e^{t}} - log t$$e^{-t} = 1 - e^{-t} - log t$$2 e^{-t} = 1 - log t$This equation cant be solved using normal methods. Hence, if it is an objective question, you have to put values in it to get the answer. Maybe the question is wrong too.Thanks & RegardsBharat Bajajaskiitian facultyIIT Delhi

3 years ago
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