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tejas sanjay akole Grade: 12
        

find:


lim    (xcosx-log(1+x))/x2


x→0


 


 


 

7 years ago

Answers : (1)

Vanya Saxena
18 Points
										

On putting the limits we find the function to be in an indeterminate form.


Thus on applying L hospital's rule we get


x->0lim [cosx-xsinx-(1/1+x)]/2x


Then on differentiating again we get


limx->0[-sinx-sinx-xcosx+(1/1+x)2]/2


on putting the limits we get the answer as  1/2


 


 


 

7 years ago
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