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dy/dx +[(x2-1)(y2-1)]1/2/xy=0
Dear upendra
or ydy/(y2-1)1/2 = - dx (x2-1)1/2/x
or ydy/(y2-1)1/2 = - dx (x2-1)/x(x2-1)1/2
or ydy/(y2-1)1/2 = x dx /x2(x2-1)1/2 -xdx /(x2-1)1/2
now intigrate
(y2-1)1/2 = tan-1(x2-1)1/2 - (x2-1)1/2
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