Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        let 'f' be a continuous function on 'R' such that
f(1/2n)=(sin(en))e-n^2+2[n]2 /n2+[n]+1 where [.] denotes greatest integer function. Then find the value of f(0).```
8 years ago

147 Points
```										Dear Paidepelly
f(1/2n)=(sin(en))e-n^2+2[n]2 /(n2+[n]+1)
for f(0) take limit n tends to infinity both side
Lt n→∞ f(1/2n)=Lt n→∞(sin(en))e-n^2+2[n]2 /(n2+[n]+1)
f(0)=Lt n→∞(sin(en))e-n^2+2[n]2 /(n2+[n]+1)
=Lt n→∞(sin(en))e-n^2+ Lt n→∞   2[n]2 /(n2+[n]+1)
=0  +Lt n→∞   2[n]2 /(n2+[n]+1)
let n=[n] +f wher f is fractional part of n
so f(0) =Lt n→∞   2(n-f)2 /(n2+n-f+1)
find limit
f(0) =2

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20
Get extra Rs. 339 off
USE CODE: CHEM20