Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        [f ( x )]101    =
1 + ∫0xf(t) dt
[ f (100)]101     =?```
7 years ago

147 Points
```										Dear DInesh

[f ( x )]101    =        1 + ∫0xf(t) dt
differentiate
101[f ( x )]100 f'(x) =f(x)
101[f ( x )]99 f'(x) =1
now integrate
101 ∫ [f ( x )]99 f'(x)dx =∫dx
101/100 [f ( x )]100  =x +c
at x=0      f(x) =1 from given relation
so value of c is 101/100
so
101/100 [f ( x )]100  =x +101/100
[f ( x )]100    =100/101 x +1

or    [f ( x )]101    =[100/101 x +1]101/100

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin

```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details