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```        A balloon is rising vertically above a level, a straight road a constant rate 1 m/s. Just when the balloon is 65m above the ground, a bicycle moving at a constant rate of 17 m/s passes under it. How fast is the distance b/w the bicycle and balloon increasing 3 seconds later?
A)11 m/s
B) 9 m/s
C) 13 m/s
D) 15 m/s```
5 years ago

Arun Kumar
IIT Delhi
256 Points
```										we do this by coordinate geometry baloon (0,65+1*t)bicycle (17t,0)z^2=289*t^2+(65+t)^22zdz/dt=289*2*t+2(65+t)we can dz/dt=11
```
3 years ago
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