MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Priyansh Soni Grade:
        

A balloon is rising vertically above a level, a straight road a constant rate 1 m/s. Just when the balloon is 65m above the ground, a bicycle moving at a constant rate of 17 m/s passes under it. How fast is the distance b/w the bicycle and balloon increasing 3 seconds later?


A)11 m/s


B) 9 m/s


C) 13 m/s


D) 15 m/s

5 years ago

Answers : (1)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
										we do this by coordinate geometry baloon (0,65+1*t)
bicycle (17t,0)
z^2=289*t^2+(65+t)^2
2zdz/dt=289*2*t+2(65+t)
we can dz/dt=11
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 2,385 off
USE CODE: COUPON10
Get extra Rs. 254 off
USE CODE: COUPON10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details