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```        for the function to be cont & diff at x=0.
what will be the value of n?
f(x) =      xn sin 1/x        x not 0
0                 x =0```
8 years ago

147 Points
```										Dear dinesh

f(x) =      xn sin 1/x        x not 0
0                 x =0
for differentiability at x=0
RHD     f'(0)= lim x tends to 0+  {f(x)-f(0)}/(x-0)
=lim x tends to 0+  xn-1 sin1/x
limit exixt for n>=1    and sin(1/x)   always lies between -1 to 1

LHD f'(0)= lim x tends to 0-     {f(x)-f(0)}/(x-0)
=lim x tends to 0-        xn-1 sin1/x
limit exixt for n>=1    and sin(1/x)   always lies between -1 to 1
LHD =RHD  only possible for n>=1

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8 years ago
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