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`        In a triangle ABC, AB=AC and the length of the median from B to the side AC is 1. Find the cosine of the angle A for which the area of triangle is minimun.`
8 years ago

147 Points
```										Dear harshit

cosA =((b/2)2 +c2 -1) /bc

b=c
so   cos A = 5/4   -1/b2
b2=4/(5-4cosA)

nor area of triangle is =1/2 bc sinA
=1/2 b2 sinA
=2sinA/(5-4cosA)
now differntiate and value of cos A for minimum value of area

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8 years ago
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