Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Yashawant Dhula Grade: Upto college level
        Find the derivative of sinx to the poer n like square 2 cube 3 its poer is 3, by first principle method.
8 years ago

bharat bajaj
IIT Delhi
123 Points
										$f(x) = \lim_{h\rightarrow 0} \frac{f(x+h) - f(x)}{h}$$f(x) = sin ^{2} x$$f(x) = \lim_{h\rightarrow 0} \frac{sin ^{2} (x+h) - sin ^{2} x}{h}$$f(x) = \lim_{h\rightarrow 0} \frac{(sin (x+h) + sin x).(sin(x+h) - sin x)}{h}$$f(x) = \lim_{h\rightarrow 0} \frac{4 sin(x+h/2).cos(h/2). cos(x+h/2).sin(h/2)}{h}$$f(x) = \lim_{h\rightarrow 0} \frac{sin(h/2)}{h/2}.2 sin(x).cos(0). cos (x)$$f(x) = 1.2 sin(x). cos (x)$$f'(x) = sin (2x)$Thanks & RegardsBharat Bajajaskiitian facultyIIT Delhi

3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details