f(x)= sinx-cosx+2^1/2 whole divided by x^3/2 where x belongs to[Π/4,5Π/4].let m the minimum value of f(x) and M be the max value of f(x).then [2M/5m] where [.] denotes greatest integer function

2 years ago

Share

Answers : (1)

                                        

Hi Debadutta,


 


The given expression is


S = [√2*sin(x-Π/4) + √2] / x3/2 = √2 [sin(x-Π/4) + 1] / x3/2


 


Note that (x-Π/4) ε [0,Π].


So clearly S is maximum when x=Π/4, and minimum when x=5Π/4.


 


So now you can find what [2M/5m] will be.


 


Regards,


Ashwin.

2 years ago

Post Your Answer

More Questions On Differential Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
Total number of solution 2 x +3 x +4 x -5 x =0 Thanks
 
 
Ans: There is only one solution that lie b/w 2 & 3. So both values have opposite sign, so f(x) should be zero b/w somewhere. You can see it from the graph also. Thanks & Regards...
  img
Jitender Singh one month ago
If the curve ( equation in image) has its local extremum at x=d then 0 -3 image attached .
 
 
Ans: Hello Student, Please find answer to your question below To find maxima & minima If you just need to find the point of minima, then is minima. Because So. x = -3 is the minima.
  img
Jitender Singh 20 days ago
Total number of solutions x 2 -4-[x]=0
 
 
2 Solve it graphically.
 
Drake one month ago
View all Questions »