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                   If f(x1 + x2 + ... + xn) = f(x1)f(x2)...f(xn) for all x belongs to real; and f(0) = 2 and  f(m) > 0 where m,n belong to natural and m is even and n is odd. 

Evaluate lim ((f(x)-1)/x) where x tends to zero.

3 years ago


Answers : (2)

                                        The answer is 1
3 years ago

Can you kindly give me the solution for the problem?

3 years ago

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is it an indeterminate form??? see photo
Yes and its value will be 0
Vijay Mukati 2 months ago
0/0 form but neumerator has value exactly = 0 but denominator tends to 0 therefore its value is
Aakash 2 months ago
yes it is an indeterminante form
vedant patil 2 months ago
Plz solve this
HInt:- For first question replace x + y = t and try to find it out. For second apply the formula of product rule of differenciation.
Vijay Mukati 2 months ago
Prove that, If y = Sin -1 x, x ∈ (–1, 1) then dy/dx =1/√(1-x 2)
y = Sin -1 x ⇒ x = sin y dy/dx=cosy dy/dx=(dx/dy) -1 =1/cosy=1/ √(1-sin 2 y) =1/√(1-x 2 )
RAJU 27 days ago
y = Sin -1 x ⇒ x = sin y dy/dx=cosy dy/dx=(dx/dy) -1 =1/cosy=1/ √(1-sin 2 y) =1/√(1-x 2 )
Raghu Vamshi Hemadri 22 days ago
How to find projection of one vector over another?
let say we have to find projection of a on b then it is given by a.b /I bI
Abhishek Singh 8 months ago
1/sinx can be written as cosecx and the integral of cosecx is log |cosecx – cotx|. Therefore,
Athiyaman one month ago
1/2cos2x is thebest answer
ranadeeshwar one month ago
Nikhil Upadhyay one month ago
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