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				   which book should i follow for quality preparation of IIT for "Calculus". i am preaparing for 2013 exams.
				   

4 years ago

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Answers : (1)

										

Hi Kumar,


 


From the perspective of IIT JEE, Arihant Series of Calculus will be a very good source.


It has theory as well as problems in detial.


 


All the best.


Regards,


Ashwin (IIT Madras).

4 years ago

Post Your Answer

Can u solve it? Question number 13 plz
 
 
By expanding the tan2x and cos2x terms we get simplifying we get now each of the multiplying term has limit 1 as x tends to 0 thus L = 1/2
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Riddhish Bhalodia 3 months ago
The minimum value of the polynomial x(x+1)(x+2)(x+3) is: a) 0 b) 9/16 c) -1 d) -3/2 ? Please answer in detail.
 
 
HInt: Expand the brackets and use the differnciation method to find it. Thanks.
  img
Vijay Mukati 10 months ago
Help Please
 
 
We start with substituting x = a + t, and hence as x tends to a, t tends to 0. so the limit now becomes this can be written in form of standard limit multiples as now as per the standard...
  img
Riddhish Bhalodia 3 months ago
what is the remainder when 45^17^17 is divided by 204
 
 
Ohh yes you can use 45.(2045)^144 . write 2025 as factor + remainder of 204. Then use binomial to get answer
  img
Sourabh Singh 2 months ago
 
This is 45^289.Expand using binomial and you will get the answer like 45.45^288 45.1225^144 Use binomial expansion now
  img
Sourabh Singh 2 months ago
 
The answer for your question is 2.942973243e+475 all th best for your bright future this is correct answer
 
Prabhakar ch 2 months ago
Dear sir/ma'am Please answer my questions.
 
 
okay that is
 
surya one year ago
 
okay
 
surya one year ago
Sir please answer and specify the reason.
 
 
∫ nx n-1 /(1+x). dx = (∫ n.x n-1 .dx)/(1+x) | 0 1 – ∫ (∫n.x n-1 .dx).d /dx (1 /(1+x) ), using recerse chain rule for integration. ∫ n.x n-1 .dx = x n and d /dx (1 /(1+x) ) = -1 /(1+x) 2 ,...
 
Akshay 10 months ago
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