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If cosy=xcos(a+y). And dx/dy =k/1+(x)2-2xcosa...... Then find value of k Now my main question is..For above que. We should diff. w.r.t "y" and we get k=sina.. ..And i see same que in diff book like this mainor.. .... If cosy=xcos(a+y). And dy/dx =k/1+(x)2-2xcosa...... Then find value of k ,and for this we should diff w.r.t "x"..And we get same ans. K=sina then for this que. We prove dy/dx=dx/dy... Thanks

4 years ago

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may be the question is wrong or may be the value ofdy/dx ...or dx/dy are equal to 1 at k = sina

3 years ago

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Lim x->0 (xcosx-log(1+x))/x^2.Limx->0 (xcosx - x )/x^2 (by elimination )Lim x->0 (cosx - x)/xWhich is finally equal to zero but while using expansion and L hospital`s rule i get the answer...
 
 
Lim x->0 (xcosx-log(1+x))/x^2 from this to the below written statement Limx->0 (xcosx - x )/x^2 How you get this ??
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Sourabh Singh one month ago
limit x tends to infinty :(2^x-1)/(2^x-1) ..please find it s answer..
 
 
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vikas yadav 6 days ago
find the equation of a line passing through the point 3,2 and perpendicular to the line x=y
 
 
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Avani Patidar 10 months ago
Integrate log(sinx+cosx)dx from -pi/4 to pi/4. someone plz help
 
 
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Riddhish Bhalodia 4 months ago
A circle passes through the point (3,(7/2)^0.5) and touches the line pair x^2 – y^2 -2x+1=0. the co ordinates of centre of circle are? (4,0) (6,0)
 
 
OK so first we solve for the lines whihc gives the two lines as and now plotting them on the coordinate axes, it’s easy to see by symmetry that the center of circle would lie on x-...
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Riddhish Bhalodia 4 months ago
(A-B)^3=
 
 
(a^3-b^3-3a^2b+3ab^2
 
charan 8 months ago
 
a^3-b^3-3a^2b+3ab^2
 
OUTPASS 8 months ago
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