MY CART (5)

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price:

There are no items in this cart.
Continue Shopping
                   what is the solution of-

( xy sinxy+ cosxy)ydx+(xysinxy-cosxy)xdy=0

3 years ago

Share

Answers : (1)

                                        

Dear Rupali,


Just rearrange the terms to get ,


(xy sinxy + cosxy)y/ (xysinxy - cosxy)x = dy/dx


then substitute xy by z,


Thus you will get your answer.


Best Of luck


Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple  to download the toolbar….


So start the brain storming…. become a leader with Elite Expert League ASKIITIANS


Thanks


Aman Bansal


Askiitian Expert

3 years ago

Post Your Answer

More Questions On Differential Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
can u provide more questions and answers in differetiation?
 
 
Hello student You can log in to Askiitians website to get the questions and answers of various topics. Contact askiitians to get the customised solutions to your queries regarding anything...
  img
Sourabh Singh 6 months ago
Please tell how they calculate it sir please see attachment
 
 
use induction principle to verify for n=1 = 5+1/1 + 0/1=6 2+4=6 means for n=1 it is correct , lets prove assume it true for n, and try to prove for n+1.
  img
Sher Mohammad 8 months ago
 
Hello student, Please find answer to your question
  img
Jitender Singh 8 months ago
 
Hello student, Please find answer to your question
  img
Jitender Singh 8 months ago
m=2-(3)^(1/2) Find the value of (m^6+m^5+m^4+1)/m^3
 
 
Hello student, This may help you m = 2 – 3^(1/2), and rationalising this we get m + 1/m = 4. som^2 = 4m-1 Given equation is= (m^3+1/m^3) +m^2+m From the identity if a+b+c = 0 gives...
  img
SHAIK AASIF AHAMED 8 months ago
 
Hello student, Please find the answer to your question below as m= m 2 =7- m 3 =26-15 1/m 3 =26+15 Given (m 6 +m 5 +m 4 +1)/m 3 =m+m 2+ m 3 +1/m 3 =2- +7-4 +26-15 +26+15 =61-5
  img
SHAIK AASIF AHAMED 8 months ago
 
m = 2 – 3^(1/2), and so m + 1/m = 4. We can also write this last equation as m^2 = 4m-1 Given expression = (m^3+1/m^3) +m^2+m Now, using the identity: a+b+c = 0 implies a^3+b^3+c^3 = 3abc,...
 
mycroft holmes 8 months ago
lim x tends to 0 ( (cosecx - cotx )/ x )
 
 
but it still comes 0/0 right...shudnt v differentiate again and then the answer comes ½
 
Shahbaz Basheer one month ago
 
Use L Hospitals rule ie, differenciate the numerator and denominator wrt x (separately), then we get lim x tends to 0 -(cosecx*cotx)- (cosecx*cosecx) which is obviously 0. Please approve the...
 
Ram Ganesh one month ago
if cos x + cos y = 4/5, cosx – cos y = 2/7 then the value of 14 tan(x-y)/2 + 5 cot (x+y)/2 is
 
 
Hello student, Please find the answer to your question below Use the following formulas to solve this questions CosC + CosD = 2Cos[(C+D)/2]Cos[(C-D)/2] CosC - CosD =...
  img
Nishant Vora 6 months ago
View all Questions »