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```				   Find the general solution of the differential equation:( (xlogx) dy/dx ) + y = (2/x) logx
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4 years ago

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```										This is solved by integrating factor method.$\frac{\mathrm{d} y}{\mathrm{d} x}+y/(xlog(x))=2/x^2 \\=>\int 1/xlog(x)dx=log(log(x)) \\=>e^{log(log(x))}(\frac{\mathrm{d} y}{\mathrm{d} x}+y/(xlog(x))=2/x^2) \\=>e^{log(log(x))}*y=\int e^{log(log(x))}/x^2dx=\int log(x)/x^2dx=-e^{-log(x)}+c$Should be enough.Arun KumarIIT DelhiAskiitians Faculty
```
2 years ago

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