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```				   Find the general solution of the differential equation:( (xlogx) dy/dx ) + y = (2/x) logx
```

4 years ago

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```										This is solved by integrating factor method.$\frac{\mathrm{d} y}{\mathrm{d} x}+y/(xlog(x))=2/x^2 \\=>\int 1/xlog(x)dx=log(log(x)) \\=>e^{log(log(x))}(\frac{\mathrm{d} y}{\mathrm{d} x}+y/(xlog(x))=2/x^2) \\=>e^{log(log(x))}*y=\int e^{log(log(x))}/x^2dx=\int log(x)/x^2dx=-e^{-log(x)}+c$Should be enough.Arun KumarIIT DelhiAskiitians Faculty
```
one year ago

how to find n-th derivative of a function f(x)=[x^(n)]logx what will be n-th derivate of f(x)

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best book for calculus for iit and school 1)sk goyal 2)amit m agrwal

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 vivek 7 months ago
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Hii the question is incomplete .Kindly repost the question and we will get back at you

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Dear student, The question is incomplete. Pls post correct question again Thanks

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