Total Price:

There are no items in this cart.
Continue Shopping
                   can i get a demo class on its yheory part?

3 years ago


Answers : (1)


Dear Monika,

yes you can get demo class on theory classes , Use the link given on askiitians website.

Best Of luck

Cracking IIT just got more exciting,It’s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple  to download the toolbar….

So start the brain storming…. become a leader with Elite Expert League ASKIITIANS


Aman Bansal

Askiitian Expert


3 years ago

Post Your Answer

More Questions On Differential Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details
Why is equation (1) not a polynomial equation and equation (2) not a polynomial in y? (1) dy/dx + sin(dy/dx) = 0 (2) (dy/dx) 2 +(dy/dx) - sin 2 y = 0
Being a equation and a polynomial equation is very different. Functions like sinx, lnx, e x are not considered polynomial quations. They are transcental functions.
Nibir Pawan Das 5 months ago
@Yugabrat sinx=0 is also a equation..
Shibashis Mallik 5 months ago
As sin is present...
Yugabrat Gogoi 5 months ago
Q. F( x + 2y, x – 2y) = xy , then F(X,Y) EQUALS- x 2 - y 2 /8 x 2 – y 2 /4 x 2 + y 2 /4 x 2 – y 2 /2
Ans: x 2 - y 2 /8 if, F(xy) = x 2 – y 2 /8, then F( x + 2y, x – 2y) = ( x+2y) 2 – (x-2y) 2 /8 = 4*x*2y/8 = xy Hence ans is x 2 - y 2 /8
Y RAJYALAKSHMI 6 months ago
TANGENTS AND NORMALS find the points on the curve 2a^2y=x^3 – 3ax^2 where the tangent is parallel to x axis
Ans: Hello Student, Please find answer to your question below Slope = 0 Put in curve:
Jitender Singh 6 months ago
what is the method to find range.
Hello student, Please find the answer to your question below Method 1 of 4: Finding the Range of a Function Given a Formula 1 Write down the formula.Let's say the formula you're...
Yugabrat Gogoi 6 months ago
Find the equation of the line passing through the point (2,3) and at a distance of 3 units from the origin.
let eqn. of line be y-3=m(x-2), where m is slope of line dist. from origin = 3 I0-3-m(0-2)I/(1+m 2 ) 1/2 =3 solving we get , m=0 or -12/5 lines are y=0 or 5y+12x=39
Abhishek Singh 29 days ago
If x+y+z=1 Then (1-3x^2-3y^2-3z^2+2x^3+2y^3+2z^3)=?
Hello Student, Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
Arun Kumar 8 months ago
View all Questions »