if f:R->[pi/6,pi/2),f(x)= arcsin (x^2 - a/x^2 + 1) is a onto function,den set of values of "a" is.....


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                                        Ans:$y = sin^{-1}(x^{2}-\frac{a}{x^{2}}+1)$$(x^{2}-\frac{a}{x^{2}}+1)=siny$$x^{4}+(1-siny)x^{2}-a=0$This is simple Quadratic in x2,$\Delta \geq 0$$(1-siny)^{2}\geq 4.(-a)$$sin^{2}y-2siny+1+4a\geq 0$$\Delta <0$$4<4(4a+1)$$a>0$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 months ago

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