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`        if the sum of two numbers is 3 then the maximum value of the product  of the first and the square of second is`
8 years ago

Pratham Ashish
17 Points
```										hi,
let one no. be  a   (0=< a  = <3 )
other no. will be 3- a
so, we have to maximize (3-a ) * a^2
let p =  (3-a ) * a^2
dp/da =  6a - 3a^2
= 0
emplies,    either a= 0 , or
a =2
d^2 p / da^2 =  6 - 6a
so, at a = 0 , we will have a min .  (d^2 p / da^2 >0 )
d^3 p / da^3  =  -6   emplies that at a= 2 we will get a max.
so the max. value will be 4.
```
8 years ago
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