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pallavi pradeep bhardwaj Grade:
        

A ladder 5m is resting against vertical waall.The bottom of the ladder is pulled along the ground away from the wall at the rate of 1.5m/sec.The length of the highest point of the ladder when the foot of the ladder is 4.0m away from the wall decreases at the rate of

7 years ago

Answers : (2)

Pratham Ashish
17 Points
										hi,



let the length of the highest point of the ladder = h

distance of the bottom from wall = d


so, h^2 + d^2 = 5^2

h^2 + d^2 = 25


h = (25 - d^2 )^1/2


dh/dt = - 1/2 (25 - d^2 )^ -1/2 * 2d

= - 4 / 3 ,

rate of decreas of h 4/3 m/s

7 years ago
anandpal shekhawat
8 Points
										Hi, 

let a be vertical height & b be distance of bottom from wall, so
a^2 + b^2 =25
when b = 4m then a = 3m
& Diff. above w.r.t. dt, we can find speed of highest point
7 years ago
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