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```				   A ladder 5m is resting against vertical waall.The bottom of the ladder is pulled along the ground away from the wall at the rate of 1.5m/sec.The length of the highest point of the ladder when the foot of the ladder is 4.0m away from the wall decreases at the rate of
```

7 years ago

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```										hi,

let the length of the highest point of the ladder   =  h

distance of the bottom from wall  =  d

so,   h^2  +  d^2 =  5^2

h^2  +  d^2 =   25

h  =  (25 - d^2 )^1/2

dh/dt  = - 1/2 (25 - d^2 )^ -1/2  *  2d

= - 4 / 3  ,

rate of decreas of h  4/3 m/s

```
7 years ago
```										Hi,
let a be vertical height & b be distance of bottom from wall, so
a^2 + b^2 =25
when b = 4m then a = 3m
& Diff. above w.r.t. dt, we can find speed of highest point
```
7 years ago

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