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The range of the function ƒ(x)=sin(sin-1{x}) where {.} is fractional part of x, is............
Hi,
this is very easy ,if u think logically
the range of {x} =(0,1)
sin inverse of {x} will giv the value of theta (sine of which is 0 to 1 ,leaving the 0 & 1 both)
now sine of that theta will be (0,1)
other way u can look that sin(sin^-1(x)) = x if x = [0,1] & {x} = ( 0,1) which is subset of [0,1]
GOOD LUCK
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