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ANKUR GUPTA Grade: 12
        

The number of roots of the equation,


cot x=π/2+x in [-π,3π/2] is,

8 years ago

Answers : (1)

anandpal shekhawat
8 Points
										hi,

put x = cot^-1(#)
so, it becomes
# = pie/2 + cot^-1(#)
& #-pie/2 = cot^-1(#)
# = -cot{pie/2 - #}
implies # = -tan(#)
& from above # = cotx
implies cotx = -tan(cotx)
in above domain this eqn is satisfied by
x = {-pie/2, pie/2, 3pie/2}
so no. of roots are 3.
8 years ago
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