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```				   if {x} and [x] represent fractional and intergral part of x , then find the value of
[x]+ 2000∑r=1{x+r}/2000
```

7 years ago

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### Answers : (1)

```										Hi anurag,

[x]+ 2000∑r=1{x+r}/2000
since {1+x}={x}

{2+x}={x}
{3+x}={x}
.
.
.
.
{r+x}={x}
the equation becomes,[x]+{x}×2000/2000 =[x] + {x} =x

```
7 years ago

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