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```				   Let x and y be real numbers satisfying the eqn x2 - 4x + y2 + 3 =0. If the max and min values of x2+y2 are a and b respectively, then show that the numerical value of a-b is 8
```

7 years ago

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```										the given equation is a circle with centre (2,0) and radius of 1 unit
(x-2)2+x2=1
the genral point on circle in polar form is : ( 2+cos x , sin x )
on putting in x2+y2 ,
(2+cos x)2+(sin x)2 = -4.sin x
sinx has max. and min. values at 1 , -1
-4 < (2+cos x)2+(sin x)2  < 4
the numerical value: a-b = 8
--
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.Regards,Ramesh   IIT Kgp - 05 batch
```
7 years ago

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