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1. Sin^-1x+sin^-1=π/2 thendy/dx

1.


Sin^-1x+sin^-1=π/2 thendy/dx

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1 Answers

Ramesh V
70 Points
14 years ago

1/(1-x2)1/2 +  1/(1-y2)1/2.dy/dx = 0

dy/dx = - (1-y2)1/2 / (1-x2)1/2

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