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pallavi pradeep bhardwaj Grade: 12
        

If the normal to the curve y=f (x) at the point (3, 4) makes an angle 3 p/4 with the positive x-axis then f' (3) =
(A) –1                                      (B) –3/4
(C) 4/3                                

8 years ago

Answers : (2)

AskIITian Expert Priyasheel - IITD
8 Points
										

y =f(x)


Slope of the normal at (x,y) to the curve = -1/f'(x)


Given, -1/f'(x) = tan (3pi/4) =-1,


So, f'(3)=1.

8 years ago
Sudheesh Singanamalla
114 Points
										

Slope of normal to y = f(x) at (3,4) is -1/f'(3). Thus


-1 / f'(3) = tan (3∏ / 4 ) = tan(∏/2 + ∏/4) = -cot(∏/4) = -1


=> f'(3) = 1


 


Hope that helps :)

7 years ago
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