Let f(x)= ∫e x (x-1)(x-2) dx. Then f decreases in the interval : (A) (∞,-2) (B) (–2, –1) (C) (1, 2) (D) (2,+∞)

Question

Let f(x)= &int;e x (x-1)(x-2) dx. Then f decreases in the interval : (A) (&infin;,-2) (B) (&ndash;2, &ndash;1) (C) (1, 2) (D) (2,+&infin;)

askiitian.expert- chandra sekhar · Answer

Hi pallavi, f(x)= &int;e x (x-1)(x-2) dx f 1 (x)=df(x)/dx = e x (x-1)(x-2) + C e x > 0 (x-1)(x-2) &ge;0 when x&le;1 and x&ge;2 (x-1)(x-2) < 0 when 1<x<2 therefore e x (x-1)(x-2) < 0 when 1<x<2 f 1 (x) < 0 when 1<x<2 f decreases in the interval (1,2)

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Let f(x)= ∫e x (x-1)(x-2) dx. Then f decreases in the interval : (A) (∞,-2) (B) (–2, –1) (C) (1, 2) (D) (2,+∞)

Let f(x)= ∫ex (x-1)(x-2) dx. Then f decreases in the interval :

(A) (∞,-2) (B) (–2, –1)
(C) (1, 2) (D) (2,+∞)

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Let f(x)= ∫e x (x-1)(x-2) dx. Then f decreases in the interval : (A) (∞,-2) (B) (–2, –1) (C) (1, 2) (D) (2,+∞)

Let f(x)= ∫ex (x-1)(x-2) dx. Then f decreases in the interval : (A) (∞,-2) (B) (–2, –1) (C) (1, 2) (D) (2,+∞)

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Let f(x)= ∫ex (x-1)(x-2) dx. Then f decreases in the interval :

(A) (∞,-2) (B) (–2, –1)
(C) (1, 2) (D) (2,+∞)