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```				   If x2+ y2=1, then : (A) yy'" - 2(y ' )2+1=0                                  (B) yy'' + (y ' )2+1=0 (C) yy " = (y ' )2-1=0                                   (D) yy''+2(y ' )2+1=0
```

7 years ago

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```										x^2 + y^2 = 1,
Differentiate w.r.t. x,
2x + 2yy' = 0,
Again differentiate,
2 + 2( yy'' +y'^2) = 0,
or, yy'' + y'^2 + 1 = 0,
ANS is (B).
```
7 years ago
```										differnciating x^2 + y^2 w.r.t.  x we get
2x + 2yy' = 0  or x + yy' = 0
again differenciating w.r.t x we get
1+y'y' + yy'' = 0 or 1 + (y')^2 + yy'' = 0
```
6 years ago

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