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pallavi pradeep bhardwaj Grade: 12
        

If x2+ y2=1, then :
(A) yy'" - 2(y ' )2+1=0                                  (B) yy'' + (y ' )2+1=0
(C) yy " = (y ' )2-1=0                                   (D) yy''+2(y ' )2+1=0

7 years ago

Answers : (2)

AskIITian Expert Priyasheel - IITD
8 Points
										

x^2 + y^2 = 1,


Differentiate w.r.t. x,


2x + 2yy' = 0,


Again differentiate,


2 + 2( yy'' +y'^2) = 0,


or, yy'' + y'^2 + 1 = 0,


ANS is (B).

7 years ago
Sudheesh Singanamalla
114 Points
										

differnciating x^2 + y^2 w.r.t.  x we get


2x + 2yy' = 0  or x + yy' = 0


again differenciating w.r.t x we get


1+y'y' + yy'' = 0 or 1 + (y')^2 + yy'' = 0


so answer is (B)

6 years ago
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