Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2 Then dy/dx

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Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2 Then dy/dx

Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2
Then dy/dx

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Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2 Then dy/dx

Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2 Then dy/dx

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Y=ƒ(2x-1)/x^2+1)ƒ?(x)= sinx^2
Then dy/dx