Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        diff(sine-1(1-x2/1+x2)) where x=atany`
6 years ago

## Answers : (1)

85 Points
```										Dear Saurabh,

=  1 / √1 - (1-x2/1+x2)2 * diff. (1-x2/1+x2)
= 1 /√ [1 + x4 + 2x2 - (1 + x4 - 2x2)/1 + x4 + 2x2]  * diff. (1-x2/1+x2)
= 1/ [√  4x2 /1 + x4 + 2x2] * diff. (1-x2/1+x2)
= 1/ [2x/1+x2] * diff. (1-x2/1+x2)
= [1 + x2/2 ]* diff. (1-x2/1+x2)
= [1 + x2/2 ]* [ (1+x2)* - 2x - (1-x2)2x ]/(1+x2)2
= -2x/(1+x2)

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Anil Pannikar
IIT Bombay
```
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details