MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
anjali SHARMA Grade: 12
        

I am new in differential equation. I just want to solve the following problem,


Can any one give me the step wise solution for this question???


Determine the equation of the tangent line for the function


                                       f(x) = x2 + 1 at point (3,10).

8 years ago

Answers : (1)

ronit bhatiya
14 Points
										

Find the slope of the function by differentiation

f '(x) = 2x



Plug in the certain point's values Since this function does not have y we don't plug in y yet

f '(3) = 6 {6 is now the slope of the point 3,10}



Plug both slope and point values into a linear equation

(y - y1) = m(x - x1) {this is the linear equation}

(y - 10) = 6(x - 3)  {Which can be simplified as below}

y = 6x -8



Just as we can find the slope and equation of a tangent line for a function, we can also do the same for a normal line. However, the normal line has two differences from the tangent line.



1. The slope of a normal line is perpendicular to the slope of the tangent line. Or in other words, the negative inverse of the tangent line.



2. The normal line is only defined if x does not = 0.



As a result, to find the slope and equation of the normal line, follow the steps above and convert the slope of the tangent line to the slope of the normal line.

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details