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baha jaff Grade: 12
        

find


please with explenation

6 years ago

Answers : (1)

suryakanth AskiitiansExpert-IITB
105 Points
										

Dear Baha,


AS limit x-> 0+


mod(x+1) is always positive


and mod(x-1) = (1-x) because for a small nighobur hood in 0+ the value of x-1 comes out to be negative


Hence for limit x->0+


hte functions is =  (x+1-(1-x))/x = 2


As limit x->0-


mod(x+1) is always positive for a samll neighbour hood in 0- x+1 is alwyas positive


mod(x-1) is = -(x-1)


Hence for limit x->0-


((x+1)- (-(x-1))) /x = 2


Hence the answer is 2


Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.


All the best.


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Askiitians Expert


Suryakanth –IITB

6 years ago
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