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`        Find parameter p so that y = 3x is a tangent line to the curve  y = x 2 + p `
7 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear nitin,

The slope of the tangent is equal to 3. At the point of tangency y ' = 3.   y ' = 2 x = 3
Solve the equation 2 x = 3 to find the x coordinate of the point of tangency.   x = 3 / 2
The point of tangency is on the line y = 3 x, therefore the y coordinate of the point of tangency is equal to   y = 3 (3/2) = 9 / 2
The point of tangency (3 / 2 , 9 / 2) is on the curve y = x 2 + p and is therefore used to find p as follows   9 / 2 = (3 / 2) 2 + p
Solve the above for p to obtain   p = 9 / 4

We are all  IITians and here to help you in your IIT  JEE preparation.  All the best.

Sagar Singh
B.Tech IIT Delhi

```
7 years ago
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