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the number of tangents to the curve y^(2)-2x^(3)-4y+8=0that passes through (1,2) is

plz answer the question briefly so that i can understand it......

6 years ago


Answers : (1)


Dear Vikash,


find dy/dx of the curve which the slope of tangent.

2y dy/dx - 6x2 - 4 dy/dx = o

dy/dx = 6x2/ 2y - 4

at (1,2) ,  dy/dx  = ∞ which means tangent is perpendicular to x axis.


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Anil Pannikar

IIT Bombay



6 years ago

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