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The limit of x tends to 0 ((x^5)^1/x^2)^1/x whole divided (x^5)^(5/x^2)

The limit of x tends to 0 ((x^5)^1/x^2)^1/x whole divided (x^5)^(5/x^2)

Grade:Upto college level

1 Answers

Rahul askIITiansExpert.IITR
110 Points
13 years ago
frankly speaking I cudn't put your question into paper.

please reframe it using the tools above.

please

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