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Dear rohit
x^2+y^2= l^2
x is the foot distance and y is the height at which top point of ladder touched wall
differentin you can get
2xdx/dt = -2ydy/dt
x=4
l=6
dx/dt = 0.5
so y = 4.472
dy/dt=0.447
In the same way for the second part dy/dt = dx/dt
so y=x
so y=x =3*2^0.5
Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed solution very quickly.All the best.
Regards,Askiitians ExpertsPrudhvi Teja
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