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For x<0, f(x)= 1+x3. Therefore g(f(x))= g(1+x3)= (1+x3-1)1/3= x.
for x> or =0, f(x)=x2-1. therefore g(f(x))= g(x2-1)=( x2-1+1)1/2= x.
threfore g(f(x))=x for all x belonging to (-infinity,infinity).
Thanks,
Saineel.
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