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`        Let there be a quotient of two natural numbers in which denominator is one less than square of numerator. If we add 2 to both num. and den. the quotient will excess 2/3. If we subtract 3 from num. as well as den. the quotient will lie between 0 and 1/10. Determine the quotient.`
7 years ago

Arun Kumar
IIT Delhi
256 Points
```										if we try to solve itn/d=qd=n^2-1(n+2)/(n^2+1)=q+2/3q=n/(n^2-1)we get a equation(n+2)/(n^2+1)=n/(n^2-1)+2/3we get2n^4-3n^3-3n^2+6n+4=0one possible solution n=-1something missing in the question
```
3 years ago
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