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A S Grade: 12
        

Let there be a quotient of two natural numbers in which denominator is one less than square of numerator. If we add 2 to both num. and den. the quotient will excess 2/3. If we subtract 3 from num. as well as den. the quotient will lie between 0 and 1/10. Determine the quotient.

7 years ago

Answers : (1)

Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
										if we try to solve it
n/d=q
d=n^2-1

(n+2)/(n^2+1)=q+2/3
q=n/(n^2-1)

we get a equation
(n+2)/(n^2+1)=n/(n^2-1)+2/3
we get
2n^4-3n^3-3n^2+6n+4=0
one possible solution n=-1

something missing in the question
3 years ago
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