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The value of limx→∞ ( 2x2 +3 / 2x2 +5 )8x(square) +3 is :-

6 years ago


Answers : (1)



The answer is


y = limx->∞ (2x2+3/2x2+5)8x^2 + 3

take log both side

logy = limx->∞ log (1 - 2/2x2+5)/{1/8x2+3}

Solve it using L Hospitals rule

logy = -8

=> y = e-8

6 years ago

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