The number of points (x,y) (where x and y both are perfect squares of integers) on the parabola y^2=px,p being a prime number, is ?

Question

Y RAJYALAKSHMI · Answer

y 2 = px y = sqrt(px) Since x & y are perfect square integers, sqrt(x) is an integer. Since p is a prime no., sqrt(p) is an irrational no. The point which satisfies the given condition is only (0, 0). The no. of points is 1.

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The number of points (x,y) (where x and y both are perfect squares of integers) on the parabola y^2=px,p being a prime number, is ?

The number of points (x,y) (where x and y both are perfect squares of integers) on the parabola y^2=px,p being a prime number, is ?

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The number of points (x,y) (where x and y both are perfect squares of integers) on the parabola y^2=px,p being a prime number, is ?

The number of points (x,y) (where x and y both are perfect squares of integers) on the parabola y^2=px,p being a prime number, is ?

1 Answers

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Other Related Questions on Analytical Geometry

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