The abscissa of 2 points A,B are the roots of equation x^2+2x-a^2=0 and ordinate are roots of equation y^2+4y-b^2=0 .Find equation of circle with AB diameter??

Question

Ritesh Khatri · Answer

Let A(x 1 ,y 1 ) and B(x 2 ,y 2 ) Eqn of circle is (x – x 1 )(x – x 2 ) + (y – y 1 )(y – y 2 ) = 0 x 2 – (x 1 + x 2 )x +x 1 x 2 + y 2 – (y 1 + y 2 )y +y 1 y 2 = 0 x 2 – (-2)x + (-a 2 )+ y 2 – (-4)y +(-b 2 ) = 0 x 2 + 2x – a 2 + y 2 + 4y – b 2 = 0 x 2 + y 2 + 2x + 4y – a 2 – b 2 = 0 is required eqn

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The abscissa of 2 points A,B are the roots of equation x^2+2x-a^2=0 and ordinate are roots of equation y^2+4y-b^2=0 .Find equation of circle with AB diameter??

The abscissa of 2 points A,B are the roots of equation x^2+2x-a^2=0 and ordinate are roots of equation y^2+4y-b^2=0 .Find equation of circle with AB diameter??

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The abscissa of 2 points A,B are the roots of equation x^2+2x-a^2=0 and ordinate are roots of equation y^2+4y-b^2=0 .Find equation of circle with AB diameter??

The abscissa of 2 points A,B are the roots of equation x^2+2x-a^2=0 and ordinate are roots of equation y^2+4y-b^2=0 .Find equation of circle with AB diameter??

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