Sin^-1{1÷i(z-1)},where z is non real can be the angle of triangle if

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Pranjal · Answer

Take z=x+iyAnd solve by taking sin on inverse function in LHS and theta on RHSFurther devide x+iy-1 by iAnd equate it by sin theta To get y=sin theta and x-1=0..

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Sin^-1{1÷i(z-1)},where z is non real can be the angle of triangle if

Sin^-1{1÷i(z-1)},where z is non real can be the angle of triangle if

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Sin^-1{1÷i(z-1)},where z is non real can be the angle of triangle if

Sin^-1{1÷i(z-1)},where z is non real can be the angle of triangle if

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