In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again
at points A₁, B₁, C₁, respectively. If angle ABC = 45° then angle A₁B₁C₁ equals

Question

In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again at points A 1 , B 1 , C 1 , respectively. If angle ABC = 45° then angle A 1 B 1 C 1 equals

Latika Leekha · Answer

Hello student, We are given that &ang;ABC = 45&deg; So, &ang;BCH = 45&deg; = &ang;BCA 1 &ang;C 1 CA 1 = 45&deg; + 45&deg; = 90&deg; So, &ang;C 1 B 1 A 1 = 90&deg; Hence, the required angle &ang;A 1 B 1 C 1 = 90&deg;.

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In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again at points A 1 , B 1 , C 1 , respectively. If angle ABC = 45° then angle A 1 B 1 C 1 equals

In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again
at points A₁, B₁, C₁, respectively. If angle ABC = 45° then angle A₁B₁C₁ equals

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In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again at points A 1 , B 1 , C 1 , respectively. If angle ABC = 45° then angle A 1 B 1 C 1 equals

In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle againat points A1, B1, C1, respectively. If angle ABC = 45° then angle A1B1C1 equals

1 Answers

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In an acute-angled triangle ABC, the altitudes from A, B, C when extended intersect the circumcircle again
at points A₁, B₁, C₁, respectively. If angle ABC = 45° then angle A₁B₁C₁ equals