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If p=(0,1,0) and Q=(0,0,1)then the projection of PQ on the plane x+y+z=3

If p=(0,1,0) and Q=(0,0,1)then the projection of PQ on the plane x+y+z=3

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Dear student
 
PQ = (0, -1, 1)
Now
Perpendicular dr of plane = (1,1,1)
Now
Hence
Sin@ = PQ. n/|PQ|*|n|
Sin@ = (0,-1,1).(1,1,1)/ |PQ|*|n| = 0
Hence 
@ = 0 degrees
 
Now projection of PQ on plane = PQ cos @ = \sqrt2
 
Regards
Arun (askIITians forum expert)

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