From points on the circle x2+y^2=a2 tangents are drawn to the hyperbola x2-y2=a2 prove that the locus of the mid point of the cord of contact is the curve (x2-y2)^2= a^2(x^2+y^2)

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Arun · Answer

I am telling you the way by which you can solve this, Let the point on circle is (a cos@, a sin@) Now you have to find the locus of mid point of chord of contact to hyperbola Put T = S 1 You will definitely get your answer Regards Arun (askIITians forum expert)

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From points on the circle x2+y^2=a2 tangents are drawn to the hyperbola x2-y2=a2 prove that the locus of the mid point of the cord of contact is the curve (x2-y2)^2= a^2(x^2+y^2)

From points on the circle x2+y^2=a2 tangents are drawn to the hyperbola x2-y2=a2 prove that the locus of the mid point of the cord of contact is the curve (x2-y2)^2= a^2(x^2+y^2)

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From points on the circle x2+y^2=a2 tangents are drawn to the hyperbola x2-y2=a2 prove that the locus of the mid point of the cord of contact is the curve (x2-y2)^2= a^2(x^2+y^2)

From points on the circle x2+y^2=a2 tangents are drawn to the hyperbola x2-y2=a2 prove that the locus of the mid point of the cord of contact is the curve (x2-y2)^2= a^2(x^2+y^2)

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