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Line parallel to 3x-4y+6=0 is 3x-4y=c
Let c be any constant.
Here equation of circle will be
(x-1)^2 +(y-2)^2 = 3^2.
So center of circle is (1,2)
Radius= 3
So distance of 3x-4y-c= 0 from (1,2) is equal to 3.
So,| (3–4*2-c)| /(3^2+4^2)^0.5 =3.
=> so c= -20 ,10.
So eqns will be
3x-4y=10 and
3x-4y=-20
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