C 2 H 5 OH + 4I 2 + 3Na 2 CO 3 ---- X + HCOONa + 5NaI + 3CO 2 + 2H 2 O In the above reaction ‘X’ is?

Question

C 2 H 5 OH + 4I 2 + 3Na 2 CO 3 ----> X + HCOONa + 5NaI + 3CO 2 + 2H 2 O In the above reaction ‘X’ is?

M Vinod Kumar · Answer

X is CHI3. Anyone can easily answer this question. You can form a table that contains reactants and products on either sides. Balance the elements according to the number of moles of the reactants and products. Hence in the above reaction, one carbon, one hydrogen`s and three iodine`s are missing. So the missing compound X is Iodoform.

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C 2 H 5 OH + 4I 2 + 3Na 2 CO 3 ----> X + HCOONa + 5NaI + 3CO 2 + 2H 2 O In the above reaction ‘X’ is?

C₂H₅OH + 4I₂ + 3Na₂CO₃ ----> X + HCOONa + 5NaI + 3CO₂ + 2H₂O
In the above reaction ‘X’ is?

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C 2 H 5 OH + 4I 2 + 3Na 2 CO 3 ----> X + HCOONa + 5NaI + 3CO 2 + 2H 2 O In the above reaction ‘X’ is?

C2H5OH + 4I2 + 3Na2CO3 ----> X + HCOONa + 5NaI + 3CO2 + 2H2OIn the above reaction ‘X’ is?

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C₂H₅OH + 4I₂ + 3Na₂CO₃ ----> X + HCOONa + 5NaI + 3CO₂ + 2H₂O
In the above reaction ‘X’ is?