A rectangle ABCD is inscribed in the circle x^2 + y^2 + 3x + 12y + 2 = 0. If the coordinates of A and B are respectively (3, – 2) and (–2, 0) then the coordinates of the mid-point of CD are

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Saurabh Koranglekar · Answer

Dear student angle DAB is 90 so BD is the diameter similarly, AC is the diameter which can be found thus C and D Regards

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A rectangle ABCD is inscribed in the circle x^2 + y^2 + 3x + 12y + 2 = 0. If the coordinates of A and B are respectively (3, – 2) and (–2, 0) then the coordinates of the mid-point of CD are

A rectangle ABCD is inscribed in the circle x^2 + y^2 + 3x + 12y + 2 = 0. If the coordinates of A and B are respectively (3, – 2) and (–2, 0) then the coordinates of the mid-point of CD are

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A rectangle ABCD is inscribed in the circle x^2 + y^2 + 3x + 12y + 2 = 0. If the coordinates of A and B are respectively (3, – 2) and (–2, 0) then the coordinates of the mid-point of CD are

A rectangle ABCD is inscribed in the circle x^2 + y^2 + 3x + 12y + 2 = 0. If the coordinates of A and B are respectively (3, – 2) and (–2, 0) then the coordinates of the mid-point of CD are

1 Answers

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